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Physics · Nuclear Physics

JEE Main 2025 — 8 April, Evening Shift — Question 50

For a nucleus of mass number AA and radius RR, the mass density of nucleus can be represented as

  1. Option A:

    A3A^{3}

  2. Option B:

    A23A^{\frac{2}{3}}

  3. Option C:

    A13A^{\frac{1}{3}}

  4. Option D:

    Independent of AA

    Correct

Answer: D

Step-by-step solution

R=R0A1/3R=R_{0} A^{1 / 3} Density = Mass number  Volume =A43πR03A==\frac{\text { Mass number }}{\text { Volume }}=\frac{A}{\frac{4}{3} \pi R_{0}^{3} A}= constant

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
8 April, Evening Shift
Subject
Physics
Chapter
Nuclear Physics
Topic
Introduction to Nucleus and its constituents
For a nucleus of mass number A and radius R , the mass density of… | JEE Main 2025 PYQ with Solution · DhiX AI