Physics · Atomic Physics

JEE Main 2026 — 22 January, Evening Shift — Question 38

Five positive charges each having charge $q$ are placed at the vertices of a pentagon as shown in the figure. The electric potential ( $V$ ) and the electric field ( $\vec{E}$ ) at the center O of the pentagon due to these five positive charges are :

Option A:
$V=\frac{5 q}{4 \pi \varepsilon_{0} r}$ and $\vec{E}=0$
Correct
Option B:
$V=\frac{5 q}{4 \pi \varepsilon_{0} r}$ and $\vec{E}=\frac{5 \sqrt{3} q}{8 \pi \varepsilon_{0} r^{2}} \hat{r}$
Option C:
$V=\frac{5 q}{4 \pi \varepsilon_{0} r}$ and $\vec{E}=\frac{5 q}{4 \pi \varepsilon_{0} r^{2}} \hat{r}$
Option D:
$V=0$ and $\vec{E}=0$

Answer: A

Step-by-step solution

Electric potential $\rightarrow \mathrm{V}=\frac{5 \mathrm{kq}}{\mathrm{R}}$ As regular polygon $\rightarrow \overrightarrow{\mathrm{E}}=0$

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 22 January, Evening Shift
Subject: Physics
Chapter: Atomic Physics
Topic: Photoelectric Effect

Answer: A

Step-by-step solution

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