Critical angle of incidence for a pair of optical media is 45 ° . The refractive indices of first and second media are in the ratio:

Physics · Geometrical Optics

JEE Main 2024 — 8 April, Shift 1 — Question 47

Critical angle of incidence for a pair of optical media is $45^{\circ}$ . The refractive indices of first and second media are in the ratio:

$\quad \sin \theta_{c}=\frac{\mu_{R}}{\mu_{d}}=\frac{\mu_{2}}{\mu_{1}}$

$\sin 45^{\circ}=\frac{\mu_{2}}{\mu_{1}}$

$\Rightarrow \frac{1}{\sqrt{2}}=\frac{\mu_{2}}{\mu_{1}}$

$\Rightarrow \frac{\mu_{1}}{\mu_{2}}=\frac{\sqrt{2}}{1}$

Answer key and solution verified before publishing.

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