Physics · Electrostatics

JEE Main 2025 — 2 April, Morning Shift — Question 62

Consider two infinitely large plane parallel conducting plates as shown below. Two plates are uniformly charged with a surface charge density $+\sigma$ and $-2 \sigma$ . The force experienced by a point charge $+q$ placed at the mid point between two plates will be :

Option A:
$\frac{3 \sigma q}{4 \varepsilon_{0}}$
Option B:
$\frac{\sigma q}{2 \varepsilon_{0}}$
Option C:
$\frac{3 \sigma q}{2 \varepsilon_{0}}$
Correct
Option D:
$\frac{\sigma q}{4 \varepsilon_{0}}$

Answer: C

Step-by-step solution

$E=\frac{2 \sigma}{2 \varepsilon_{0}}+\frac{\sigma}{2 \varepsilon_{0}}=\frac{3 \sigma}{2 \varepsilon_{0}}$

$F=E q=\frac{3 \sigma q}{2 \varepsilon_{0}}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 2 April, Morning Shift
Subject: Physics
Chapter: Electrostatics
Topic: Properties of Electric Charge and Coulomb's Law

Answer: C

Step-by-step solution

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