Chemistry · Nitrogen Containing Organic Compounds

JEE Main 2026 — 6 April, Morning Shift — Question 64

Consider the following sequence of reactions. The percentage of nitrogen in the yellow product ( X ) formed is $\_\_\_\_$ %. (Nearest Integer) (Given Molar mass in $\mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{~N}: 14$ )

Answer: 21

Numerical answer — enter this value.

Step-by-step solution

HCl catalysed hydrolysis. \item Aniline acts as a solvent and reactant.

The mixture is gently heated to facilitate rearrangement.

After the reaction is complete, the mixture is cooled and treated with acetic acid to neutralise excess acid and precipitate the final product. Mass percentage of nitrogen in final product $=\frac{42}{197} \times 100=21.30 \% \approx 21$

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Exam: JEE Main 2026
Paper: 6 April, Morning Shift
Subject: Chemistry
Chapter: Nitrogen Containing Organic Compounds
Topic: Diazonium salts