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Chemistry · Alcohols, Ethers and Phenols

JEE Main 2026 — 6 April, Morning Shift — Question 65

4.7 g of phenol is heated with Zn to give product X . If this reaction goes to 60%60 \% completion then the number of moles of compound X formed will be ____\_\_\_\_ ×10−2\times 10^{-2} (Nearest Integer) (Given molar mass in gmol−1:H:1,C:12,O:16\mathrm{g} \mathrm{mol}^{-1}: \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{O}: 16 )

Answer: 3

Numerical answer — enter this value.

Step-by-step solution

Moles of phenol =4.794.0=0.05 mol=\frac{4.7}{94.0}=0.05 \mathrm{~mol} Reaction is 1:11: 1 so 0.05 mole of phenol will give 0.05 mole of benzene on 100%100 \% yield

For 60%60 \% yield =0.05×0.60=0.05 \times 0.60

=0.03 mol.=0.03 \mathrm{~mol} .

mol of ' X ' =3×10−2 mol=3 \times 10^{-2} \mathrm{~mol} So answer is

Solution figure

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Exam
JEE Main 2026
Paper
6 April, Morning Shift
Subject
Chemistry
Chapter
Alcohols, Ethers and Phenols
Topic
Phenols

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