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Chemistry · Nitrogen Containing Organic Compounds

JEE Main 2026 — 21 January, Morning Shift — Question 66

Consider the following reaction sequence The percentage of nitrogen in product ' T ' formed is ____\_\_\_\_ %\%. (Nearest integer) (Given molar mass in gmol−1H:1,C:12, N:14,O:16\mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{~N}: 14, \mathrm{O}: 16 )

Question figure

Answer: 20

Numerical answer — enter this value.

Step-by-step solution

Mol. wt =6×12+(6×1)+(2×14)+(2×16)=138=6 \times 12+(6 \times 1)+(2 \times 14)+(2 \times 16) =138 % N=28138×100=20.29%\% \mathrm{~N}=\frac{28}{138} \times 100=20.29 \%

Solution figure

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Exam
JEE Main 2026
Paper
21 January, Morning Shift
Subject
Chemistry
Chapter
Nitrogen Containing Organic Compounds
Topic
Diazonium salts

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