Chemistry · Nitrogen Containing Organic Compounds
JEE Main 2026 — 21 January, Morning Shift — Question 50
A hydrocarbon ' P ' on reaction with HCl gives an optically active compound ' Q ' which on reaction with one mole of ammonia gives compound ' R ' . ' R ' on diazotization followed by hydrolysis gives ' S '. Identify and S .
- Option A:
- Option B:
- Option C:Correct
- Option D:
Answer: C
Step-by-step solution
\begin{aligned} &$\ce{CH3-CH=CH-CH3}$ \\ &\xrightarrow{$\ce{(P)}$ \ HCl} $\ce{CH3-CH2-CH^{+}-CH3}$ \quad (Q) \\ &\xrightarrow{$\ce{(R)}$ \ NH3} $\ce{CH3-CH2-CH(NH2)-CH3}$ \\ &\xrightarrow{$\ce{NaNO2}$ \ aq.\ HCl \ (S)} $\ce{CH3-CH2-CH(OH)-CH3}$ \end{aligned}
Answer key and solution verified before publishing.
Practise Nitrogen Containing Organic Compounds
Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.
- Exam
- JEE Main 2026
- Subject
- Chemistry
- Chapter
- Nitrogen Containing Organic Compounds
- Topic
- Introduction & Preparation of Amines