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Physics · Units, Dimensions & Error Analysis

JEE Main 2026 — 8 April, Evening Shift — Question 2

Consider the equation H=xpeqErts\mathrm{H} = \frac{\mathrm{x}^{\mathrm{p}}\mathrm{e}^{\mathrm{q}}\mathrm{E}^{\mathrm{r}}}{\mathrm{t}^{\mathrm{s}}} where H=\mathrm{H} = magnetic field E=\mathrm{E} = electric field ϵ=\epsilon = permittivity, x=\mathrm{x} = distance, t=\mathrm{t} = time. The values of p, q, r and s respectively are:

  1. Option A:

    1, 1, 1, 1

    Correct
  2. Option B:

    -1, 1, 2, 1

  3. Option C:

    1, -1, -2, 1

  4. Option D:

    -1, -2, -2, 1

Answer: A

Step-by-step solution

Considering H as magnetic field intensity (current per unit length), dimensional analysis yields p=1, q=1, r=1, s=1, which matches option (1).

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Exam
JEE Main 2026
Paper
8 April, Evening Shift
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Units and Dimensions Analysis

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