Physics · Horizontal Circular Motion

JEE Main 2026 — 8 April, Evening Shift — Question 3

A car moving with a speed of $54\mathrm{km/h}$ takes a turn of radius $20\mathrm{m}$ . A simple pendulum is suspended from the ceiling of the car. Determine the angle made by the string of the pendulum with the vertical during the turning. (Take $\mathrm{g} = 10\mathrm{m/s}^2$ )

Option A:
$\tan^{-1}(0.5)$
Option B:
$\tan^{-1}(0.75)$
Option C:
$\tan^{-1}(1.125)$
Correct
Option D:
$\tan^{-1}(0.25)$

Answer: C

Step-by-step solution

$v = 54\,\text{km/h} = 15\,\text{m/s}$ . $\tan\theta = \frac{v^2}{rg} = \frac{225}{20\times10} = 1.125$ . Thus $\theta = \tan^{-1}(1.125)$ .

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 8 April, Evening Shift
Subject: Physics
Chapter: Horizontal Circular Motion
Topic: Dynamics of circular motion