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Chemistry · Ionic Equilibrium

JEE Main 2026 — 28 January, Morning Shift — Question 64

Consider the dissociation equilibrium of the following weak acid HA⇌H+(aq)+A−(aq)\mathrm{HA} \rightleftharpoons \mathrm{H}^{+}(\mathrm{aq})+\mathrm{A}^{-}(\mathrm{aq}) If the pKa of the acid is 4 , then the pH of 10 mM HA solution is ____\_\_\_\_ . (Nearest integer) [Given : The degree of dissociation can be neglected with respect to unity]

Answer: 3

Numerical answer — enter this value.

Step-by-step solution

pH=12[pKa−log⁡c]\mathrm{pH}=\frac{1}{2}\left[\mathrm{pK}_{\mathrm{a}}-\log \mathrm{c}\right] pH=12[4−log⁡10−2]pH=3\begin{aligned} & \mathrm{pH}=\frac{1}{2}\left[4-\log 10^{-2}\right] \\& \mathrm{pH}=3 \end{aligned}

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
28 January, Morning Shift
Subject
Chemistry
Chapter
Ionic Equilibrium
Topic
Solutions containing one Acid or Base

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