JEE Main 2026 — 28 January, Morning Shift — Question 48

$\underset{0.02 \mathrm{M}}{\mathrm{HCl}}+\underset{0.02 \mathrm{M}}{\mathrm{B}} \rightarrow \mathrm{BH}^{+}+\mathrm{Cl}^{-}$ $\mathrm{t}_{\mathrm{f}} 0 0.02 \mathrm{ym}-0.02 \mathrm{x} 0.02 \mathrm{x}$ $\mathrm{pOH}=\mathrm{pK}_{\mathrm{b}}+\log \left[\frac{\text { Salt }}{\text { Base }}\right]$ $5=5.699+\log \left[\frac{\text { Salt }}{\text { Base }}\right]$ $\frac{\mathrm{x}}{\mathrm{y}-\mathrm{x}}=\frac{1}{5}$ $6 \mathrm{x}=\mathrm{y}$ $7 \mathrm{x}=100$ $\mathrm{x}=\frac{100}{7} \mathrm{ml}$ $\& \mathrm{y}=\frac{600}{7} \mathrm{ml}$