Consider ' n ' is the number of lone pair of electrons present in the equatorial position of the most stable structure of ClF 3 . The ions from the following with ' n ' number of unpaired electrons are : A. V 3+ B. Ti 3+ C. Cu 2+ D. Ni 2+ E. Ti 2+ C hoose the correct answer from the options given below :

Chemistry · Chemical Bonding

JEE Main 2025 — 28 January, Morning Shift — Question 31

Consider ' $n$ ' is the number of lone pair of electrons present in the equatorial position of the most stable structure of $\mathrm{ClF}_{3}$ . The ions from the following with ' n ' number of unpaired electrons are :

A. $\mathrm{V}^{3+}$

B. $\mathrm{Ti}^{3+}$

C. $\mathrm{Cu}^{2+}$

D. $\mathrm{Ni}^{2+}$

E. $\mathrm{Ti}^{2+}$ C

hoose the correct answer from the options given below :

Option A:
A and C only
Option B:
A, D and E only
Correct
Option C:
B and C only
Option D:
B and D only

Answer: B

Step-by-step solution

$\mathrm{ClF}_{3}$

$\mathrm{n}=2$ (No of lone pair present in equitorial plane) (Unpaired $\mathrm{e}^{-}$ )

(A) $\mathrm{V}^{+3}:[\mathrm{Ar}] 3 \mathrm{~d}^{2} \quad 2$

(B) $\mathrm{Ti}^{3+}:[\mathrm{Ar}] 3 \mathrm{~d}^{1} \quad 1$

(D) $\mathrm{Ni}^{+2}:[\mathrm{Ar}] 3 \mathrm{~d}^{8} \quad 2$

(E) $\mathrm{Ti}^{+2}:[\mathrm{Ar}] 3 \mathrm{~d}^{2} \quad 2$

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Exam: JEE Main 2025
Paper: 28 January, Morning Shift
Subject: Chemistry
Chapter: Chemical Bonding
Topic: Hybridization and VSEPR

The molecules having square pyramidal geometry are

Answer: B

Step-by-step solution

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