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Physics · System Of Particles

JEE Main 2025 — 23 January, Morning Shift — Question 63

Consider a circular disc of radius 20 cm with centre located at the origin. A circular hole of a radius 5 cm is cut from this disc in such a way that the edge of the hole touches the edge of the disc. The distance of centre of mass of residual or remaining disc from the origin will be-

  1. Option A:

    2.0cm

  2. Option B:

    0.5cm

  3. Option C:

    1.5cm

  4. Option D:

    1.0cm

    Correct

Answer: D

Step-by-step solution

mass of disc =m=m

mass of cut part =m16=\frac{\mathrm{m}}{16}

Xcom =m×0−m16×15m−m16X_{\text {com }}=\frac{m \times 0-\frac{m}{16} \times 15}{m-\frac{m}{16}}

=1 cm=1 \mathrm{~cm}.

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
23 January, Morning Shift
Subject
Physics
Chapter
System Of Particles
Topic
Position of Center of Mass
Consider a circular disc of radius 20 cm with centre located at the… | JEE Main 2025 PYQ with Solution · DhiX AI