Physics · Semiconductor and Electronic Devices

JEE Main 2025 — 3 April, Morning Shift — Question 55

Choose the correct logic circuit for the given truth table having inputs AA and BB.

InputsOutput
ABY
000
010
101
111
  1. Option A:
    Option A figure
  2. Option B:
    Option B figure
    Correct
  3. Option C:
    Option C figure
  4. Option D:
    Option D figure

Answer: B

Step-by-step solution

Option (1) =(A+B‾)⋅A=(\overline{A+B}) \cdot A

=(Aˉ+Bˉ)⋅A≡0=(\bar{A}+\bar{B}) \cdot A \equiv 0

Option (2) =(A+B)⋅A=(A+B) \cdot A

A⋅A+A⋅B=AA \cdot A+A \cdot B=A

Option (3) (A+B)⋅Aˉ(A+B) \cdot \bar{A}

A⋅Aˉ+Aˉ⋅B=AˉBA \cdot \bar{A}+\bar{A} \cdot B=\bar{A} B

Option (4) (A+B)⋅(B)(A+B) \cdot(B)

A⋅B+B⋅B=BA \cdot B+B \cdot B=B

⇒\Rightarrow option 2 matches the truth table

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Physics
Chapter
Semiconductor and Electronic Devices
Topic
Boolean Algebra, Truth Tables and Logic Gates
Choose the correct logic circuit for the given truth table having… | JEE Main 2025 PYQ with Solution · DhiX AI