Physics · Capacitors and R-C Circuits

JEE Main 2025 — 23 January, Evening Shift — Question 69

At steady state the charge on the capacitor, as shown in the circuit below, is $\qquad$ $\mu \mathrm{C}$ .

Answer: 16

Numerical answer — enter this value.

$\mathrm{i}=\left(\frac{5}{25}\right)$

$\mathrm{Q}=\mathrm{CV}$

$\mathrm{Q}=\left(8 \times 10^{-6}\right)\left(\frac{5}{25} \times 10\right)$

$\mathrm{Q}=\left(\frac{8 \times 5 \times 10^{-2}}{25}\right)=16 \mu \mathrm{C}$

Answer key and solution verified before publishing.

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