JEE Main 2024 — 6 April, Shift 2 — Question 35

At surface:

$\mathrm{mg}=300 \mathrm{~N}$ $\mathrm{m}=\frac{300}{\mathrm{~g}_{\mathrm{s}}}$

At Depth $\frac{R}{4}: g_{d}=g_{s}\left[1-\frac{d}{R}\right]$ $g_{d}=g_{s}\left[1-\frac{R}{4 R}\right]$

$g_{d}=\frac{3 g_{s}}{4}$

weight at depth $$\begin{aligned} & =\mathrm{m} \times \mathrm{g}{\mathrm{d}} & =\mathrm{m} \times \frac{3 \mathrm{~g}{\mathrm{s}}}{4} & =\frac{3}{4} \times 300 & =225 \mathrm{~N} \end{aligned}$$