Physics · Geometrical Optics
JEE Main 2026 — 6 April, Evening Shift — Question 14
Angle of minimum deviation is equal to the half of the angle of prism in an equilateral prism. The refractive index of the prism is
- Option A:
1.5
- Option B:
- Option C:Correct
- Option D:
1.65
Answer: C
Step-by-step solution
For equilateral prism, A=60°. Given \delta_m = A/2 = 30°. Then \mu = \frac{\sin((A+\delta_m)/2)}{\sin(A/2)} = \frac{\sin45°}{\sin30°} = \frac{1/\sqrt{2}}{1/2} = \sqrt{2}.
Answer key and solution verified before publishing.
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- Exam
- JEE Main 2026
- Subject
- Physics
- Chapter
- Geometrical Optics
- Topic
- Apparent Depth, Glass Slab, Prism and Dispersion