Chemistry · Coordination Compounds

JEE Main 2024 — 1 February, Shift 2 — Question 73

[Co(NH3)6]3+\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+} and [CoF6]3−\left[\mathrm{CoF}_{6}\right]^{3-} are respectively known as:

  1. Option A:

    Spin free Complex, Spin paired Complex

  2. Option B:

    Spin paired Complex, Spin free Complex

    Correct
  3. Option C:

    Outer orbital Complex, Inner orbital Complex

  4. Option D:

    Inner orbital Complex, Spin paired Complex

Answer: B

Step-by-step solution

[Co(NH3)6]3+\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}

Co3+(\mathrm{Co}^{3+}( strong field ligand )⇒3 d6(t2 g6,eg0)) \Rightarrow 3 \mathrm{~d}^{6}\left(\mathrm{t}_{2 \mathrm{~g}}^{6}, \mathrm{e}_{\mathrm{g}}^{0}\right),

Hybridisation: d2sp3\mathrm{d}^{2} \mathrm{sp}^{3}

Inner obital complex(spin paired complex)

Pairing will take place.

[CoF6]3−\left[\mathrm{CoF}_{6}\right]^{3-}

Co3+(\mathrm{Co}^{3+}( weak field ligand )⇒3 d6(t2 g4,eg2)) \Rightarrow 3 \mathrm{~d}^{6}\left(\mathrm{t}_{2 \mathrm{~g}}^{4}, \mathrm{e}_{\mathrm{g}}^{2}\right)

Hybridisation:

sp3 d2\mathrm{sp}^{3} \mathrm{~d}^{2}

Outer orbital complex (spin free complex)

no pairing will take place

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Chemistry
Chapter
Coordination Compounds
Topic
Properties and importance of Coordination Complexes
[ Co ( NH 3 ) 6 ] 3+ and [ CoF 6 ] 3- are respectively known as: | JEE Main 2024 PYQ with Solution · DhiX AI