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Physics · Kinetic Theory of Gases

JEE Main 2026 — 22 January, Evening Shift — Question 46

An insulated cylinder of volume 60 cm360 \mathrm{~cm}^{3} is filled with a gas at 27∘C27^{\circ} \mathrm{C} and 2 atmospheric pressure. Then the gas is compressed making the final volume as 20 cm320 \mathrm{~cm}^{3} while allowing the temperature to rise to 77∘C77^{\circ} \mathrm{C}. The final pressure is ____\_\_\_\_ atmospheric pressure.

Answer: 7

Numerical answer — enter this value.

Step-by-step solution

PV=nRT\mathrm{PV}=\mathrm{nRT}

P1 V1RT1=P2 V2RT2\frac{\mathrm{P}_{1} \mathrm{~V}_{1}}{\mathrm{RT}_{1}}=\frac{\mathrm{P}_{2} \mathrm{~V}_{2}}{\mathrm{RT}_{2}} 2×105×60300=P2×20350\frac{2 \times 10^{5} \times 60}{300}=\frac{\mathrm{P}_{2} \times 20}{350}

P2=2×105×7×36\mathrm{P}_{2}=\frac{2 \times 10^{5} \times 7 \times 3}{6} P2=7×105=7 atmP_{2}=7 \times 10^{5}=7 \mathrm{~atm}

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
22 January, Evening Shift
Subject
Physics
Chapter
Kinetic Theory of Gases
Topic
Energy of Gas and Gas Laws and Miscellaneous Problems

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