Chemistry · Periodicity of Elements and Periodic Properties

JEE Main 2025 — 29 January, Morning Shift — Question 14

An element EE has the ionisation enthalpy value of 374 kJ mol−1374\,\mathrm{kJ\,mol^{-1}}. EE reacts with elements AA, BB, CC and DD having electron gain enthalpy values of −328, −349, −325 and −295 kJ mol−1-328,\ -349,\ -325\ \text{and}\ -295\,\mathrm{kJ\,mol^{-1}}, respectively.

The correct order of the products EAEA, EBEB, ECEC and EDED in terms of ionic character is:

  1. Option A:

    EB>\mathrm{EB}> EA >> EC >> ED

    Correct
  2. Option B:

    ED>EC>EA>EB\mathrm{ED}>\mathrm{EC}>\mathrm{EA}>\mathrm{EB}

  3. Option C:

    EA>EB>EC>ED\mathrm{EA}>\mathrm{EB}>\mathrm{EC}>\mathrm{ED}

  4. Option D:

    ED>EC>EB>EA\mathrm{ED}>\mathrm{EC}>\mathrm{EB}>\mathrm{EA}

Answer: A

Step-by-step solution

Ionic character depends on the tendency of electron transfer. The greater the difference between ionisation enthalpy of EE and the electron gain enthalpy of the other element, the greater is the ionic character. Ionisation enthalpy of EE is constan i.e., 374374.

Now comparing magnitudes of electron gain enthalpy, we have

B=−349B = -349

A=−328A = -328

C=−325C = -325

D=−295D = -295

More negative electron gain enthalpy means stronger tendency to gain electron and more ionic bond formation.

Thus ionic character follows EB>EA>EC>EDEB > EA > EC > ED.

Therefore, the correct option is A.

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Chemistry
Chapter
Periodicity of Elements and Periodic Properties
Topic
Periodicity in Chemical Properties (Ionization Energy, Electron Affinity, Electronegativity)
An element E has the ionisation enthalpy value of 374\, kJ\,mol -1 .… | JEE Main 2025 PYQ with Solution · DhiX AI