Chemistry · Chemical Bonding

JEE Main 2026 — 22 January, Evening Shift — Question 54

Among $\mathrm{H}_{2} \mathrm{~S}, \mathrm{H}_{2} \mathrm{O}, \mathrm{NF}_{3}, \mathrm{NH}_{3}$ and $\mathrm{CHCl}_{3}$ , identify the molecule $(\mathrm{X})$ with lowest dipole moment value. The number of lone pairs of electrons present on the central atom of the molecule $(\mathrm{X})$ is :

Option A:
2
Option B:
0
Option C:
1
Correct
Option D:
3

Answer: C

Step-by-step solution

Molecule	Dipole moment
$\mathrm{H}_{2} \mathrm{~S}$	0.95
$\mathrm{H}_{2} \mathrm{O}$	1.85
$\mathrm{NF}_{3}$	0.23 (minimum)
$\mathrm{NH}_{3}$	1.47
$\mathrm{CHCl}_{3}$	1.04

Number of lone pair on central atom $=1$

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 22 January, Evening Shift
Subject: Chemistry
Chapter: Chemical Bonding
Topic: Dipole Moment and Fajans' Rule