JEE Main 2026 — 5 April, Morning Shift — Question 5

A wedge Y with mass of $10\mathrm{kg}$ and all frictionless surfaces and the inclined surface making $37^{\circ}$ with horizontal. A block X with mass $2\mathrm{kg}$ is placed at the highest point of the wedge as shown in figure is at rest. At $t = 0$ wedge (Y) is pulled toward right with constant force $(f)$ of $24\mathrm{N}$. Taking the block X at rest at $t = 0$, the time taken by it to slide down $8.8\mathrm{m}$ on the slope, while Y is on the move, is _s. (take $\tan 37^{\circ} = 3/4$ and $g = 10\mathrm{m/s}^2$)