Physics · Thermodynamics

JEE Main 2026 — 24 January, Morning Shift — Question 45

A voltage regulating circuit consisting of Zener diode, having break-down voltage of 10 V and maximum power dissipation of 0.4 W , is operated at 15 V . The approximate value of protective resistance in this circuit is $\_\_\_\_$ $\Omega$ .

Answer: 125

Numerical answer — enter this value.

Step-by-step solution

$P_{D}=0.4 W=10 i$ $\mathrm{i}=0.04 \mathrm{~A}$ $\mathrm{R}=\frac{15-10}{0.04}=\frac{5}{0.04}=125 \Omega$

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Exam: JEE Main 2026
Paper: 24 January, Morning Shift
Subject: Physics
Chapter: Thermodynamics
Topic: Calculation of Work, Heat and Internal Energy

Density of water at 4^circ C and 20^circ C are 1000 kg / m^3 and respectively. The increase in internal energy of 4 kg water when it is…

Answer: 125

Step-by-step solution

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