Chemistry · Biomolecules

JEE Main 2025 — 2 April, Evening Shift — Question 6

A tetrapeptide, " $x$ " on complete hydrolysis produced glycine (Gly), alanine (Ala), valine (Val), leucine (Leu) in equimolar proportion each. The number of tetrapeptides (sequences) possible involving each of these amino acids is:

Option A:
32
Option B:
24
Correct
Option C:
8
Option D:
16

Answer: B

Step-by-step solution

Let $A=$ Gly

\begin{aligned} & \mathrm{B}=\mathrm{Ala} \\& \mathrm{C}=\mathrm{Val} \\& \mathrm{D}=\mathrm{Le} \mathrm{u} \end{aligned}

Total 24 tetrapeptides are formed. The 24 tetrapeptides formed including all the four amino acids are

ABCD & BACD & CABD & DABC \\ ABDC & BADC & CADB & DACB \\ ACBD & BDAC & CBAD & DBAC \\ ACDB & BDCA & CBDA & DBCA \\ ADBC & BCAD & CDAB & DCAB \\ ADCB & BCDA & CDBA & DCBA \\ \hline {\text{Total } 24} \end{array}$$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 2 April, Evening Shift
Subject: Chemistry
Chapter: Biomolecules
Topic: Amino acids