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Physics · Mechanical Properties of Matter

JEE Main 2025 — 8 April, Evening Shift — Question 69

A sample of a liquid is kept at 1 atm. It is compressed to 5 atm which leads to change of volume of 0.8 cm30.8 \mathrm{~cm}^{3}. If the bulk modulus of the liquid is 2 GPa , the initial volume of the liquid was \qquad litre. (Take 1 atm =105 Pa=10^{5} \mathrm{~Pa} )

Answer: 4

Numerical answer — enter this value.

Step-by-step solution

−ΔvBv=ΔP⇒4×105 Pa=2×109 Pa×10−6×0.8v-\frac{\Delta v B}{v}=\Delta P \Rightarrow 4 \times 10^{5} \mathrm{~Pa}=\frac{2 \times 10^{9} \mathrm{~Pa} \times 10^{-6} \times 0.8}{v}

v=2×109×10−6×0.84×105=4×10−3 m3v=\frac{2 \times 10^{9} \times 10^{-6} \times 0.8}{4 \times 10^{5}}=4 \times 10^{-3} \mathrm{~m}^{3} ⇒4\Rightarrow 4 litre

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
8 April, Evening Shift
Subject
Physics
Chapter
Mechanical Properties of Matter
Topic
Stress,Strain and Modulus of Elasticity

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