Physics · Motion in Plane

JEE Main 2025 — 2 April, Morning Shift — Question 48

A river is flowing from west to east direction with speed of 9 km h−19 \mathrm{~km} \mathrm{~h}^{-1}. If a boat capable of moving at a maximum speed of 27 km h−127 \mathrm{~km} \mathrm{~h}^{-1} in still water, crosses the river in half a minute, while moving with maximum speed at an angle of 150∘150^{\circ} to direction of river flow, then the width of the river is

  1. Option A:

    112.5 m

    Correct
  2. Option B:

    75 m

  3. Option C:

    300 m

  4. Option D:

    112.5×3 m112.5 \times \sqrt{3} \mathrm{~m}

Answer: A

Step-by-step solution

t=wvbcos⁡(60)t=\frac{w}{v_{b} \cos (60)}

w=tvbcos⁡(60)=30×27×518×12=112.5 m\begin{aligned} w & =t v_{b} \cos (60) & =30 \times 27 \times \frac{5}{18} \times \frac{1}{2} & =112.5 \mathrm{~m} \end{aligned}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Physics
Chapter
Motion in Plane
Topic
Relative motion in Two Dimension
A river is flowing from west to east direction with speed of 9 km h… | JEE Main 2025 PYQ with Solution · DhiX AI