Physics · Rotational Dynamics

JEE Main 2024 — 27 January, Shift 2 — Question 55

A ring and a solid sphere roll down the same inclined plane without slipping. They start from rest. The radii of both bodies are identical and the ratio of their kinetic energies is $\frac{7}{x}$ where $x$ is

Answer: 7

Numerical answer — enter this value.

Step-by-step solution

In pure rolling work done by friction is zero. Hence potential energy is converted into kinetic energy.

Since initially the ring and the sphere have same potential energy, finally they will have same kinetic energy too.

$\therefore$ Ratio of kinetic energies $=1$ $\Rightarrow \frac{7}{\mathrm{x}}=1 \Rightarrow \mathrm{x}=7$

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Exam: JEE Main 2024
Paper: 27 January, Shift 2
Subject: Physics
Chapter: Rotational Dynamics
Topic: Rolling Motion

A heavy iron bar of weight 12 kg is having its one end on the ground and the other on the shoulder of a man. The rod makes an angle 60^circ…

Answer: 7

Step-by-step solution

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