Start free

Chemistry · Chemical Kinetics

JEE Main 2026 — 22 January, Morning Shift — Question 59

A → products (First order reaction).

Three sets of experiment were performed for a reaction under similar experimental conditions. Run 1⇒100 mL1 \Rightarrow 100 \mathrm{~mL} of 10 M solution of reactant A Run 2⇒200 mL2 \Rightarrow 200 \mathrm{~mL} of 10 M solution of reactant A Run 3⇒100 mL3 \Rightarrow 100 \mathrm{~mL} of 10 M solution of reactant A+\mathrm{A}+ 100 mL of H2O\mathrm{H}_{2} \mathrm{O} added. The correct variation of rate of reaction is

  1. Option A:

    Run 1=1= Run 2=2= Run 3

  2. Option B:

    Run 3<3< Run 1=1= Run 2

    Correct
  3. Option C:

    Run 3<3< Run 1<1< Run 2

  4. Option D:

    Run 1<1< Run 2<2< Run 3

Answer: B

Step-by-step solution

For I st { }^{\text {st }} order reaction Rate =k[A]=\mathrm{k}[\mathrm{A}] with decrease in concentration of A , rate of reaction decreases.

Answer key and solution verified before publishing.

Practise Chemical Kinetics

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free
Exam
JEE Main 2026
Paper
22 January, Morning Shift
Subject
Chemistry
Chapter
Chemical Kinetics
Topic
Rate Laws and Rate Constant

More Chemical Kinetics questions from this paper

A &rarr; products (First order reaction). Three sets of experiment… | JEE Main 2026 PYQ with Solution · DhiX AI