Physics · Units, Dimensions & Error Analysis

JEE Main 2025 — 3 April, Evening Shift — Question 67

A physical quantity CC is related to four other quantities p,q,rp, q, r and ss as follows C=pq2r3sC=\frac{p q^{2}}{r^{3} \sqrt{s}}.

The percentage errors in the measurement of p,q,rp, q, r and ss are 1%,2%,3%1 \%, 2 \%, 3 \% and 2%2 \%,

respectively. The percentage error in the measurement of CC will be \qquad %\%.

Answer: 15

Numerical answer — enter this value.

Step-by-step solution

ΔCC=Δpp+2Δqq+3Δrr+12Δss\frac{\Delta C}{C}=\frac{\Delta p}{p}+2 \frac{\Delta q}{q}+\frac{3 \Delta r}{r}+\frac{1}{2} \frac{\Delta s}{s}

% error =1+2×2+3×3+12×2=1+4+9+1\begin{aligned} \% \text { error } & =1+2 \times 2+3 \times 3+\frac{1}{2} \times 2 \\ & =1+4+9+1 \end{aligned} =15=15

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Significant Figures and Error Analysis
A physical quantity C is related to four other quantities p, q, r and… | JEE Main 2025 PYQ with Solution · DhiX AI