Chemistry · Thermodynamics & Thermochemistry

JEE Main 2025 — 3 April, Evening Shift — Question 18

A perfect gas ( 0.1 mol ) having $\overline{\mathrm{C}}_{\mathrm{v}}=1.50 \mathrm{R}$ (independent of temperature) undergoes the above transformation

from point 1 to point 4. If each step is reversible, the total work done (w) while going from point 1 to point 4 is (-)

$\_\_\_\_\_$ J (nearest integer) [Given: $\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ ]

Answer: 304

Numerical answer — enter this value.

$|w|=$ area under the curve

\begin{aligned} |\mathrm{w}| & =3 \times(2000-1000) \\& =3000 \mathrm{~mL} \text { atm } \\& =3 \mathrm{~L} \text { atm } \end{aligned}

|\mathrm{w}|=3 \times 101.3 \mathrm{~J}

=303.9 \mathrm{~J}

Answer key and solution verified before publishing.

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