Physics · Wave Optics

JEE Main 2024 — 8 April, Shift 1 — Question 56

A parallel beam of monochromatic light of wavelength 600 nm passes through single slit of 0.4 mm width. Angular divergence corresponding to second order minima would be $\qquad$ $\times 10^{-3} \mathrm{rad}$ .

Answer: 6

Numerical answer — enter this value.

Step-by-step solution

$\sin \theta \simeq \theta \simeq \frac{2 \lambda}{\mathrm{~b}}$

$=\frac{2 \times 600 \times 10^{-9}}{4 \times 10^{-4}}=3 \times 10^{-3} \mathrm{rad}$

Total divergence $=(3+3) \times 10^{-3}=6 \times 10^{-3} \mathrm{rad}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 8 April, Shift 1
Subject: Physics
Chapter: Wave Optics
Topic: Diffraction of Light Waves