Physics · Mechanical Properties of Matter

JEE Main 2024 — 8 April, Shift 1 — Question 53

A liquid column of height 0.04 cm balances excess pressure of soap bubble of certain radius. If density of liquid is 8×103 kg m−38 \times 10^{3} \mathrm{~kg} \mathrm{~m}^{-3} and surface tension of soap solution is 0.28Nm−10.28 \mathrm{Nm}^{-1}, then diameter of the soap bubble is \qquad cm . (if g=10 ms−2\mathrm{g}=10 \mathrm{~ms}^{-2} )

Answer: 7

Numerical answer — enter this value.

Step-by-step solution

ρgh=4SR\quad \rho g h=\frac{4 S}{R}

⇒R=4×0.288×103×10×4×10−4\Rightarrow \mathrm{R}=\frac{4 \times 0.28}{8 \times 10^{3} \times 10 \times 4 \times 10^{-4}}

⇒0.288 m=288 cm\Rightarrow \frac{0.28}{8} \mathrm{~m}=\frac{28}{8} \mathrm{~cm}

⇒R=3.5 cm\Rightarrow \mathrm{R}=3.5 \mathrm{~cm}

Diameter =7 cm=7 \mathrm{~cm}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Physics
Chapter
Mechanical Properties of Matter
Topic
Surface Tension and Surface Energy
A liquid column of height 0.04 cm balances excess pressure of soap… | JEE Main 2024 PYQ with Solution · DhiX AI