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Physics · Atomic Physics

JEE Main 2024 — 9 April, Shift 2 — Question 33

A hydrogen atom in ground state is given an energy of 10.2 eV. How many spectral lines will be emitted due to transition of electrons?

  1. Option A:

    6

  2. Option B:

    3

  3. Option C:

    10

  4. Option D:

    1

    Correct

Answer: D

Step-by-step solution

En=−13.6 1n2 eV,E2−E1=10.2 eV⇒n=2E_n = -13.6\,\frac{1}{n^2}\ \text{eV}, \quad E_2 - E_1 = 10.2\,\text{eV} \Rightarrow n=2

Number of spectral lines,

N=n(n−1)2=2(2−1)2=1N = \frac{n(n - 1)}{2} = \frac{2(2 - 1)}{2} = 1

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
9 April, Shift 2
Subject
Physics
Chapter
Atomic Physics
Topic
Hydrogen Spectrum

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