A first row transition metla (M) does not liberate H 2 gas from dilute HCl .1 mol of aqueous solution of MSO 4 is treated with excess of aqueous KCN and then H 2 S ( g ) is passed through the solution. The amount of MS (metal sulphide) formed from the above reaction is \ \ \ \ mol.

Chemistry · d and f Block Elements

JEE Main 2026 — 22 January, Morning Shift — Question 56

A first row transition metla (M) does not liberate $\mathrm{H}_{2}$ gas from dilute HCl .1 mol of aqueous solution of $\mathrm{MSO}_{4}$ is treated with excess of aqueous KCN and then $\mathrm{H}_{2} \mathrm{~S}(\mathrm{~g})$ is passed through the solution. The amount of MS (metal sulphide) formed from the above reaction is $\_\_\_\_$ mol.

Option A:
2
Option B:
1
Option C:
3
Option D:
0
Correct

Answer: D

Step-by-step solution

$\mathrm{Cu} \xrightarrow{\text { dil. } \mathrm{HCl}}$ no reaction

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 22 January, Morning Shift
Subject: Chemistry
Chapter: d and f Block Elements
Topic: Introduction and Properties of Transition Elements