A current of 200 μ A deflects the coil of a moving coil galvanometer through 60 ° . The current to cause deflection through π/10 radian is :

Physics · Current Electricity

JEE Main 2024 — 27 January, Shift 2 — Question 35

A current of $200 \mu \mathrm{~A}$ deflects the coil of a moving coil galvanometer through $60^{\circ}$ . The current to cause deflection through $\frac{\pi}{10}$ radian is :

Option A:
$30 \mu \mathrm{~A}$
Option B:
$120 \mu \mathrm{~A}$
Option C:
$60 \mu \mathrm{~A}$
Correct
Option D:
$180 \mu \mathrm{~A}$

Answer: C

Step-by-step solution

i $\propto \theta$ (angle of deflection) $\therefore \frac{\mathrm{i}_{2}}{\mathrm{i}_{1}}=\frac{\theta_{2}}{\theta_{1}} \Rightarrow \frac{\mathrm{i}_{2}}{200 \mu \mathrm{~A}}=\frac{\pi / 10}{\pi / 3}=\frac{3}{10}$

$\Rightarrow i_{2}=60 \mu \mathrm{~A}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 27 January, Shift 2
Subject: Physics
Chapter: Current Electricity
Topic: Electrical Measuring Instruments

Answer: C

Step-by-step solution

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