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Physics · Geometrical Optics

JEE Main 2025 — 8 April, Evening Shift — Question 52

A convex lens of focal length 30 cm is placed in contact with a concave lens of focal length 20 cm . An object is placed at 20 cm to the left of this lens system. The distance of the image from the lens in cm is \qquad .

  1. Option A:

    30

  2. Option B:

    607\frac{60}{7}

  3. Option C:

    15

    Correct
  4. Option D:

    45

Answer: C

Step-by-step solution

1F=1f1+1f2=130+1−20=−160\frac{1}{F}=\frac{1}{f_{1}}+\frac{1}{f_{2}}=\frac{1}{30}+\frac{1}{-20}=-\frac{1}{60}

v=Fuu+F=−60×−20−20+−60=−15 cmv=\frac{F u}{u+F}=\frac{-60 \times-20}{-20+-60}=-15 \mathrm{~cm}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
8 April, Evening Shift
Subject
Physics
Chapter
Geometrical Optics
Topic
Lenses and Their Combinations, Silvering of Lens

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