A container of fixed volume contains a gas at 27 ° C . To double the pressure of the gas, the temperature of gas should be raised to \ \ \ \ \ \ ° C .

Physics · Kinetic Theory of Gases

JEE Main 2025 — 29 January, Morning Shift — Question 41

A container of fixed volume contains a gas at $27^{\circ} \mathrm{C}$ . To double the pressure of the gas, the temperature of gas should be raised to $\_\_\_\_\_\_$ ${ }^{\circ} \mathrm{C}$ .

Answer: 327

Numerical answer — enter this value.

Step-by-step solution

$\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}$

$\frac{\mathrm{P}}{300}=\frac{2 \mathrm{P}}{\mathrm{T}_{2}}$

$\mathrm{T}_{2}=600 \mathrm{~K}$

$\mathrm{T}_{2}=327^{\circ} \mathrm{C}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 29 January, Morning Shift
Subject: Physics
Chapter: Kinetic Theory of Gases
Topic: Energy of Gas and Gas Laws and Miscellaneous Problems