Mathematics · Probability

JEE Main 2025 — 22 January, Morning Shift — Question 6

A coin is tossed three times. Let X denote the number of times a tail follows a head. If μ\mu and σ2\sigma^{2} denote the mean and variance of X , then the value of 64(μ+σ2)64\left(\mu+\sigma^{2}\right) is :

  1. Option A:

    51

  2. Option B:

    48

    Correct
  3. Option C:

    32

  4. Option D:

    64

Answer: B

Step-by-step solution

HHH→0\mathrm{HHH} \rightarrow 0

HHT →0\rightarrow 0

HTH →1\rightarrow 1

HTT →0\rightarrow 0

THH →1\rightarrow 1

THT →1\rightarrow 1

TTH →1\rightarrow 1

TTT →0\rightarrow 0

Probability distribution

figure

μ=∑xipi=12\mu=\sum \mathrm{x}_{\mathrm{i}} \mathrm{p}_{\mathrm{i}}=\frac{1}{2}

σ2=∑xi2pi−μ2\sigma^{2}=\sum x_{i}^{2} p_{i}-\mu^{2}

=12−14=14=\frac{1}{2}-\frac{1}{4}=\frac{1}{4}

64(μ+σ2)=64(12+14)=4864\left(\mu+\sigma^{2}\right)=64\left(\frac{1}{2}+\frac{1}{4}\right)=48

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Mathematics
Chapter
Probability
Topic
Mean, variance, expected values of distributions
A coin is tossed three times. Let X denote the number of times a tail… | JEE Main 2025 PYQ with Solution · DhiX AI