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Physics · Motion in Plane

JEE Main 2026 — 24 January, Morning Shift — Question 41

A boy thrown a ball into air at 45∘45^{\circ} from the horizontal to land it on a roof of a building of height H . If the ball attains maximum height in 2 s and lands on the building in 3 s after launch, then value of H is ____\_\_\_\_ m. (g=10 m/s2)\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)

  1. Option A:

    20

  2. Option B:

    10

  3. Option C:

    25

  4. Option D:

    15

    Correct

Answer: D

Step-by-step solution

T=2uyg=4\mathrm{T}=\frac{2 \mathrm{u}_{\mathrm{y}}}{\mathrm{g}}=4 ⇒uy=402=20 m/s\Rightarrow \mathrm{u}_{\mathrm{y}}=\frac{40}{2}=20 \mathrm{~m} / \mathrm{s} y=uyΔt−12 g(Δt)2\mathrm{y}=\mathrm{u}_{\mathrm{y}} \Delta \mathrm{t}-\frac{1}{2} \mathrm{~g}(\Delta \mathrm{t})^{2} ⇒H=20×3−5×9\Rightarrow \mathrm{H}=20 \times 3-5 \times 9 =60−45=60-45 =15 m=15 \mathrm{~m}

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
24 January, Morning Shift
Subject
Physics
Chapter
Motion in Plane
Topic
Oblique and Horizontal Projectile Motion
A boy thrown a ball into air at 45 ° from the horizontal to land it… | JEE Main 2026 PYQ with Solution · DhiX AI