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Physics · Newton's Laws of Motion

JEE Main 2024 — 6 April, Shift 2 — Question 42

A body of weight 200 N is suspended form a tree branch thought a chain of mass 10 kg . The branch pulls the chain by a force equal to (if g=10 m/s2g=10 \mathrm{~m} / \mathrm{s}^{2} ):

  1. Option A:

    150 N

  2. Option B:

    300 N

    Correct
  3. Option C:

    200 N

  4. Option D:

    100 N

Answer: B

Step-by-step solution

Chain block system is in equilibrium so

T=200+100=300 N\mathrm{T}=200+100=300 \mathrm{~N}.

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
6 April, Shift 2
Subject
Physics
Chapter
Newton's Laws of Motion
Topic
Application of NLM and Impulse
A body of weight 200 N is suspended form a tree branch thought a… | JEE Main 2024 PYQ with Solution · DhiX AI