Mathematics · Permutations and Combinations

JEE Main 2024 — 5 April, Shift 2 — Question 5

60 words can be made using all the letters of the word BHBJO , with or without meaning. If these words are written as in a

dictionary, then the 50th 50^{\text {th }} word is :

  1. Option A:

    OBBHJ

  2. Option B:

    HBBJO

  3. Option C:

    OBBJH

    Correct
  4. Option D:

    JBBOH

Answer: C

Step-by-step solution

Word: BHBJOBHBJO ⇒\Rightarrow Letters in order: B,B,H,J,OB,B,H,J,O

Total words=5!2!=60=\frac{5!}{2!}=60

Words starting with B=4!=24B=4!=24

Words starting with H=4!2!=12 H=\frac{4!}{2!}=12

Words starting with J=4!2!=12 J=\frac{4!}{2!}=12 Thus, words 1–481\text{–}48 are before those starting with $O

50−48=250-48=2

Remaining letters: B,B,H,JB,B,H,J

2nd arrangement in order: BBJH BBJH

OBBJH\boxed{\text{OBBJH}}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Permutations and Combinations
Topic
Applications of Permuations and Combination
60 words can be made using all the letters of the word BHBJO , with… | JEE Main 2024 PYQ with Solution · DhiX AI