Physics · Gravitation

JEE Advanced 2023 — Paper 1 — Question 23

Two satellites P and Q are moving in different circular orbits around the Earth (radius R). The heights of P and QQ from the Earth surface are hPh_{P} and hQh_{Q}, respectively, where hP=R/3h_{P}=R / 3. The accelerations of PP and QQ due to Earth's gravity are gPg_{P} and gQg_{Q}, respectively. If gP/gQ=36/25g_{P} / g_{Q}=36 / 25, what is the value of hQh_{Q} ?

  1. Option A:

    3R/53 \mathrm{R} / 5

    Correct
  2. Option B:

    R/6\mathrm{R} / 6

  3. Option C:

    6R/56 R / 5

  4. Option D:

    5R/65 R / 6

Answer: A

Step-by-step solution

gP=GM(R+R3)2 gQ=GM(R+hQ)23625=gP gQ⇒3625=R+hQ4R3⇒(4R3)⋅(65)=R+hQ⇒ hQ=3R5\begin{aligned} & g_{P}=\frac{G M}{\left(\mathrm{R}+\frac{\mathrm{R}}{3}\right)^{2}} \\ & \mathrm{~g}_{\mathrm{Q}}=\frac{\mathrm{GM}}{\left(\mathrm{R}+\mathrm{h}_{\mathrm{Q}}\right)^{2}} \\ & \frac{36}{25}=\frac{\mathrm{g}_{\mathrm{P}}}{\mathrm{~g}_{\mathrm{Q}}} \Rightarrow \sqrt{\frac{36}{25}}=\frac{\mathrm{R}+\mathrm{h}_{\mathrm{Q}}}{\frac{4 \mathrm{R}}{3}} \\ & \Rightarrow\left(\frac{4 \mathrm{R}}{3}\right) \cdot\left(\frac{6}{5}\right)=\mathrm{R}+\mathrm{h}_{\mathrm{Q}} \\ & \Rightarrow \mathrm{~h}_{\mathrm{Q}}=\frac{3 \mathrm{R}}{5} \end{aligned}

Answer key and solution verified before publishing.

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Exam
JEE Advanced 2023
Paper
Paper 1
Subject
Physics
Chapter
Gravitation
Topic
Gravitational Field and Gravity