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Physics · Electrostatics

JEE Advanced 2021 — Paper 1 — Question 37

Two point charges -Q and +Q/3+\mathrm{Q} / \sqrt{3} are placed in the xy-plane at the origin (0,0)(0,0) and a point (2,0)(2,0),respectively, as shown in the figure.This results in an equipotential circle of radius R and potential V=0\mathrm{V}=0 in the xy -plane with its center at (b, 0). All lengths are measured in meters.

The value of b is _______ meter.

Answer: 3.00

Numerical answer — enter this value.

Step-by-step solution

b=a+\text{b}=\text{a}+ radius =233+1+3=23+3+31+3=\frac{2\sqrt{3}}{\sqrt{3}+1}+\sqrt{3}=\frac{2\sqrt{3}+3+\sqrt{3}}{1+\sqrt{3}} =33+31+3=3=\frac{3\sqrt{3}+3}{1+\sqrt{3}}=3 Center =(3,0)=\left( 3,0 \right)

Answer key and solution verified before publishing.

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Exam
JEE Advanced 2021
Paper
Paper 1
Subject
Physics
Chapter
Electrostatics
Topic
Electrostatic Potential Energy and Electric Potential

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