The weight percentage of hydrogen in Q , formed in the following reaction sequence, is \ \ \ \ \ \ . conc. HNO 3 [Given: Atomic mass of H =1, C =12, N =14, O =16, S =32, Cl =35 ]

Chemistry · Aromatic Compounds

JEE Advanced 2022 — Paper 1 — Question 40

The weight percentage of hydrogen in $\mathbf{Q}$ , formed in the following reaction sequence, is $\_\_\_\_\_\_$ . conc. $\mathrm{HNO}_{3}$ [Given: Atomic mass of $\mathrm{H}=1, \mathrm{C}=12, \mathrm{~N}=14, \mathrm{O}=16, \mathrm{~S}=32, \mathrm{Cl}=35$ ]

Answer: 1.31

Numerical answer — enter this value.

Step-by-step solution

$\mathrm{C}_{6} \mathrm{H}_{3} \mathrm{O}_{7} \mathrm{~N}_{3}$

Molecular weight $=12 \times 6+1 \times 3+16 \times 7+14 \times 3$

$=72+3+112+42=229 \mathrm{gm} / \mathrm{mole}$

$\therefore$ Weight percentage of $\mathrm{H}=\frac{3}{229} \times 100=1.3100 \%$

Answer key and solution verified before publishing.

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Exam: JEE Advanced 2022
Paper: Paper 1
Subject: Chemistry
Chapter: Aromatic Compounds
Topic: Chemical Properties of Arenes - Electrophilic Aromatic Substitution