Chemistry · Hydrocarbons

JEE Advanced 2022 — Paper 1 — Question 41

If the reaction sequence given below is carried out with 15 moles of acetylene, the amount of the product D formed (in $g$ ) is $\_\_\_\_\_\_\_\_$ -. The yields of $\mathbf{A}, \mathbf{B}, \mathbf{C}$ and $\mathbf{D}$ are given in parentheses.[0pt] [Given: Atomic mass of $\mathrm{H}=1, \mathrm{C}=12, \mathrm{O}=16, \mathrm{Cl}=35$ ]

Answer: 136

Numerical answer — enter this value.

Step-by-step solution

Molecular weight $=\mathrm{C}_{8} \mathrm{H}_{8} \mathrm{O}_{2}$ $=12 \times 8+1 \times 8+16 \times 2=96+8+32=136$

Moles of product (D) formed $=\frac{15}{3} \times 0.8 \times 0.5 \times 0.5=\frac{3}{3}=1 \therefore$

Weight of product $(D)=1 \times 136=136 \mathrm{~g}$

Answer key and solution verified before publishing.

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Exam: JEE Advanced 2022
Paper: Paper 1
Subject: Chemistry
Chapter: Hydrocarbons
Topic: Properties & Uses of Alkynes