JEE Advanced 2021 — Paper 1 — Question 42

0.1 molal $\text{AgN}{{\text{O}}_{3}}\left( \text{aq} \right)$ solution $\text{AgN}{{\text{O}}_{3}}\text{A}{{\text{g}}^{+}}\left( \text{aq} \right)+\text{NO}_{3}^{-}\left( \text{aq} \right)$ $\text{i}=1+\left( 2-1 \right)\times 1=2(\alpha =1$, given $)$ $\text{ }\!\!\Delta\!\!\text{ }{{T}_{b}}=i\times {{k}_{b}}\times m$ $\text{ }\!\!\Delta\!\!\text{ }{{\text{T}}_{\text{b}}}=2\times 0.5\times 0.1=0.1$ So, boiling point of solution ' A ' is $={{100.10}^{\circ }}\text{C}=\text{x}$