Chemistry · Structure of Atom

JEE Advanced 2019 — Paper 2 — Question 16

The ground state energy of hydrogen atom is -13.6 eV . Consider an electronic state $\psi$ of $\mathrm{He}^{+}$ whose energy, azumuthal quantum number and magnetic quantum number are $-3.4 \mathrm{eV}, 2$ and 0 , respectively. Which of the following statement(s) is(are) true for the state $\Psi$ ?

Option A:
It is a 4d state
Correct
Option B:
It has 2 angular nodes
Correct
Option C:
It has 3 radial nodes
Option D:
The nuclear charge experienced by the electron in this state is less than 2 e , where e is the magnitude of the electronic charge

Answer: A, B

Step-by-step solution

$-3.4=\frac{-13.6 \times 2^{2}}{n^{2}}$

$\mathrm{n}=4$

$\ell=2$

Subshell $=4 \mathrm{~d}$

Angular nodes $=\ell=2$

Radial nodes $=\mathrm{n}-\ell-1=4-2-1=1$

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Exam: JEE Advanced 2019
Paper: Paper 2
Subject: Chemistry
Chapter: Structure of Atom
Topic: Quantum Mechanical Model of Atom - Schrödinger

Answer: A, B

Step-by-step solution

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