Chemistry · Alkyl and Aryl Halides

JEE Advanced 2020 — Paper 1 — Question 23

The cubic unit cell structure of a compound containing cation M and anion X is shown below. When compared to the anion, the cation has smaller ionic radius. Choose the correct statement(s).

Option A:
The empirical formula of the compound is MX
Correct
Option B:
The cation M and anion X have different coordination geometries
Option C:
The ratio of $\mathrm{M}-\mathrm{X}$ bond length to the cubic unit cell edge length is 0.866
Correct
Option D:
The ratio of the ionic radii of cation M to anion X is 0.414

Answer: A, C

Step-by-step solution

It can be assumed to be CsCl type solid (bcc)

So, $r_{+}+r_{-}=\frac{\sqrt{3} a}{2}=0.866$

Formula of solid = MX

$0.732 \leq \frac{r_{+}}{r_{-}} \leq 0.999$

Answer key and solution verified before publishing.

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Exam: JEE Advanced 2020
Paper: Paper 1
Subject: Chemistry
Chapter: Alkyl and Aryl Halides
Topic: Mechanism of Substitution reactions