Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

JEE Advanced 2020 — Paper 1 — Question 24

$5.00 \mathrm{~mL}$ of 0.10 M oxalic acid solution taken in a conical flask is titrated against NaOH from a burette using phenolphthalein indicator. The volume of NaOH required for the appearance of permanent faint pink color is tabulated below for five experiments. What is the concentration, in molarity, of the NaOH solution?

Exp. No.	Vol. of $\mathbf{N a O H}(\mathbf{m L})$ )
1	12.5
2	10.5
3	9.0
4	9.0
5	9.0

Answer: 0.11

Numerical answer — enter this value.

Step-by-step solution

Vol. of NaOH used at equivalent point $=9 \mathrm{~mL}$

So, mequivalent of NaOH used up to end point $=9 \times(\mathrm{M} \times 1)$

$5 \times 0.1 \times 2=9 \times M$

$\mathrm{M}=\frac{1}{9}=0.11$

Answer key and solution verified before publishing.

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Exam: JEE Advanced 2020
Paper: Paper 1
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry
Topic: Acid-Base Titrations and Related Problems